Submission #63046436


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#include <iostream>
#include <vector>
#include <queue>
#include <string>
#include <limits>
using namespace std;
int main(){
int N;
cin >> N;
vector<string> C(N);
for (int i = 0; i < N; i++){
cin >> C[i];
}
const int INF = numeric_limits<int>::max() / 2;
// dp[i][j] : i j
vector<vector<int>> dp(N, vector<int>(N, INF));
queue<pair<int,int>> que;
//
for (int i = 0; i < N; i++){
 
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#include <iostream>
#include <vector>
#include <queue>
#include <string>
#include <limits>
using namespace std;
 
int main(){
    int N;
    cin >> N;
    vector<string> C(N);
    for (int i = 0; i < N; i++){
        cin >> C[i];
    }
    const int INF = numeric_limits<int>::max() / 2;
    // dp[i][j] : 最短のパリンドローム経路の長さ(頂点 i から j)
    vector<vector<int>> dp(N, vector<int>(N, INF));
    queue<pair<int,int>> que;
 
    // 初期状態:空文字列(各頂点で始まるもの)
    for (int i = 0; i < N; i++){
        dp[i][i] = 0;
        que.push({i, i});
    }
    // 1辺のパリンドローム:単一文字はパリンドローム
    for(int i = 0; i < N; i++){
        for(int j = 0; j < N; j++){
            if(C[i][j] != '-' && dp[i][j] > 1){
                dp[i][j] = 1;
                que.push({i,j});
            }
        }
    }
 
    // 事前に各頂点への逆向き辺(pred)と各頂点から出る辺(succ)を文字ごとにまとめる
    vector<vector<vector<int>>> pred(N, vector<vector<int>>(26));
    vector<vector<vector<int>>> succ(N, vector<vector<int>>(26));
    for (int u = 0; u < N; u++){
        for (int v = 0; v < N; v++){
            char ch = C[u][v];
            if(ch == '-') continue;
            int letter = ch - 'a';
            succ[u][letter].push_back(v);
            pred[v][letter].push_back(u);
        }
    }
 
    while(!que.empty()){
        auto [i, j] = que.front();
        que.pop();
        int d = dp[i][j];
        // 両側に同じ文字を追加する
        for(int letter = 0; letter < 26; letter++){
            // i に対する逆向き辺 u->i
            const auto &vec1 = pred[i][letter];
            // j に対する順向き辺 j->v
            const auto &vec2 = succ[j][letter];
            for (int u : vec1){
                for (int v : vec2){
                    int nd = d + 2;
                    if(dp[u][v] > nd){
                        dp[u][v] = nd;
                        que.push({u,v});
                    }
                }
            }
        }
    }
 
    // 出力:各 (i,j) に対して答え
    // dp[i][j] が INF の場合はパリンドローム経路は存在しないので -1 とする
    for (int i = 0; i < N; i++){
        for (int j = 0; j < N; j++){
            if(dp[i][j] == INF) cout << -1 << " ";
            else cout << dp[i][j] << " ";
        }
        cout << "\n";
    }
    return 0;
}

Submission Info

Submission Time
Task E - Palindromic Shortest Path
User una_o0
Language C++ 20 (gcc 12.2)
Score 450
Code Size 2558 Byte
Status AC
Exec Time 11 ms
Memory 4020 KiB

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 450 / 450
Status
AC × 2
AC × 58
Set Name Test Cases
Sample sample00.txt, sample01.txt
All sample00.txt, sample01.txt, testcase00.txt, testcase01.txt, testcase02.txt, testcase03.txt, testcase04.txt, testcase05.txt, testcase06.txt, testcase07.txt, testcase08.txt, testcase09.txt, testcase10.txt, testcase11.txt, testcase12.txt, testcase13.txt, testcase14.txt, testcase15.txt, testcase16.txt, testcase17.txt, testcase18.txt, testcase19.txt, testcase20.txt, testcase21.txt, testcase22.txt, testcase23.txt, testcase24.txt, testcase25.txt, testcase26.txt, testcase27.txt, testcase28.txt, testcase29.txt, testcase30.txt, testcase31.txt, testcase32.txt, testcase33.txt, testcase34.txt, testcase35.txt, testcase36.txt, testcase37.txt, testcase38.txt, testcase39.txt, testcase40.txt, testcase41.txt, testcase42.txt, testcase43.txt, testcase44.txt, testcase45.txt, testcase46.txt, testcase47.txt, testcase48.txt, testcase49.txt, testcase50.txt, testcase51.txt, testcase52.txt, testcase53.txt, testcase54.txt, testcase55.txt
Case Name Status Exec Time Memory
sample00.txt AC 1 ms 3484 KiB
sample01.txt AC 1 ms 3488 KiB
testcase00.txt AC 1 ms 3484 KiB
testcase01.txt AC 1 ms 3488 KiB
testcase02.txt AC 2 ms 3680 KiB
testcase03.txt AC 11 ms 4020 KiB
testcase04.txt AC 1 ms 3596 KiB
testcase05.txt AC 2 ms 3680 KiB
testcase06.txt AC 2 ms 3736 KiB
testcase07.txt AC 2 ms 3684 KiB
testcase08.txt AC 2 ms 3616 KiB
testcase09.txt AC 2 ms 3904 KiB
testcase10.txt AC 1 ms 3608 KiB
testcase11.txt AC 2 ms 3760 KiB
testcase12.txt AC 2 ms 3712 KiB
testcase13.txt AC 2 ms 3756 KiB
testcase14.txt AC 1 ms 3660 KiB
testcase15.txt AC 2 ms 3672 KiB
testcase16.txt AC 1 ms 3504 KiB
testcase17.txt AC 2 ms 3732 KiB
testcase18.txt AC 1 ms 3620 KiB
testcase19.txt AC 2 ms 3756 KiB
testcase20.txt AC 1 ms 3672 KiB
testcase21.txt AC 3 ms 3764 KiB
testcase22.txt AC 3 ms 3692 KiB
testcase23.txt AC 5 ms 3852 KiB
testcase24.txt AC 2 ms 3684 KiB
testcase25.txt AC 8 ms 3928 KiB
testcase26.txt AC 2 ms 3668 KiB
testcase27.txt AC 3 ms 3892 KiB
testcase28.txt AC 2 ms 3724 KiB
testcase29.txt AC 4 ms 3792 KiB
testcase30.txt AC 2 ms 3608 KiB
testcase31.txt AC 6 ms 3724 KiB
testcase32.txt AC 2 ms 3704 KiB
testcase33.txt AC 3 ms 3824 KiB
testcase34.txt AC 2 ms 3692 KiB
testcase35.txt AC 4 ms 3920 KiB
testcase36.txt AC 3 ms 3728 KiB
testcase37.txt AC 5 ms 3800 KiB
testcase38.txt AC 2 ms 3744 KiB
testcase39.txt AC 4 ms 3888 KiB
testcase40.txt AC 4 ms 3792 KiB
testcase41.txt AC 4 ms 3788 KiB
testcase42.txt AC 2 ms 3628 KiB
testcase43.txt AC 5 ms 3880 KiB
testcase44.txt AC 2 ms 3684 KiB
testcase45.txt AC 2 ms 3704 KiB
testcase46.txt AC 2 ms 3632 KiB
testcase47.txt AC 4 ms 3824 KiB
testcase48.txt AC 4 ms 3744 KiB
testcase49.txt AC 5 ms 3732 KiB
testcase50.txt AC 3 ms 3712 KiB
testcase51.txt AC 6 ms 3888 KiB
testcase52.txt AC 2 ms 3556 KiB
testcase53.txt AC 6 ms 3976 KiB
testcase54.txt AC 5 ms 3712 KiB
testcase55.txt AC 6 ms 3920 KiB


2025-06-06 (Fri)
18:12:03 +09:00