I was wondering what the best way to match "test.this"
from "blah blah blah test.this@gmail.com blah blah"
is? Using Python.
I've tried re.split(r"\b\w.\w@")
.
A .
in regex is a metacharacter, it is used to match any character. To match a literal dot in a raw Python string (r""
or r''
), you need to escape it, so r"\."
\
(\\
) instead. So, all of these are equivalent: '\\.'
, "\\."
, r'\.'
, r"\."
. See: stackoverflow.com/a/52335971/4561887.
Commented
Mar 17, 2021 at 3:54
r"..."
syntax is Python "raw" strings, not "regular" strings.
Commented
May 27, 2021 at 16:59
'\\.'
, "\\."
, while raw strings require the single slash: r'\.'
, r"\."
, which was the entire point of my comment. This answer doesn't make that clear. I wanted to make that clear in my comment for anyone stumbling upon this answer who's using regular strings, as this answer is intended for raw strings only.
Commented
May 27, 2021 at 17:58
In your regex you need to escape the dot "\."
or use it inside a character class "[.]"
, as it is a meta-character in regex, which matches any character.
Also, you need \w+
instead of \w
to match one or more word characters.
Now, if you want the test.this
content, then split
is not what you need. split
will split your string around the test.this
. For example:
>>> re.split(r"\b\w+\.\w+@", s)
['blah blah blah ', 'gmail.com blah blah']
You can use re.findall
:
>>> re.findall(r'\w+[.]\w+(?=@)', s) # look ahead
['test.this']
>>> re.findall(r'(\w+[.]\w+)@', s) # capture group
['test.this']
"In the default mode, Dot (.) matches any character except a newline. If the DOTALL flag has been specified, this matches any character including a newline." (python Doc)
So, if you want to evaluate dot literaly, I think you should put it in square brackets:
>>> p = re.compile(r'\b(\w+[.]\w+)')
>>> resp = p.search("blah blah blah test.this@gmail.com blah blah")
>>> resp.group()
'test.this'
Here is my add-on to the main answer by @Yuushi:
These are NOT allowed.
'\.' # NOT a valid escape sequence in **regular** Python single-quoted strings
"\." # NOT a valid escape sequence in **regular** Python double-quoted strings
They'll cause a warning like this:
DeprecationWarning: invalid escape sequence
\.
All of these, however, ARE allowed and are equivalent:
# Use a DOUBLE BACK-SLASH in Python _regular_ strings
'\\.' # **regular** Python single-quoted string
"\\." # **regular** Python double-quoted string
# Use a SINGLE BACK-SLASH in Python _raw_ strings
r'\.' # Python single-quoted **raw** string
r"\." # Python double-quoted **raw** string
Keep in mind, the backslash (\
) char itself must be escaped in Python if used inside of a regular string ('some string'
or "some string"
) instead of a raw string (r'some string'
or r"some string"
). So, keep in mind the type of string you are using. To escape the dot or period (.
) inside a regular expression in a regular python string, therefore, you must also escape the backslash by using a double backslash (\\
), making the total escape sequence for the .
in the regular expression this: \\.
, as shown in the examples above.
If you want to put a literal
\
in a string you have to use\\
to escape non-alphanumeric characters of string variables, including dots, you could use re.escape
:
import re
expression = 'whatever.v1.dfc'
escaped_expression = re.escape(expression)
print(escaped_expression)
output:
whatever\.v1\.dfc
you can use the escaped expression to find/match the string literally.
So first you need to construct your regex string. For example this one matches your need:
^.*?\btest\b\.\bthis\b.*?
Next you need to put it into Python code:
import re
input_string = "blah blah blah test.this@gmail.com blah blah"
regex_string = "^.*?\\btest\\b\\.\\bthis\\b.*?"
if re.search(regex_string, input_string):
print("match :-)")
else:
print("no match :-(")
To understand what the regex does, you can play with that on regex101.com.
This expression,
(?<=\s|^)[^.\s]+\.[^.\s]+(?=@)
might also work OK for those specific types of input strings.
import re
expression = r'(?<=^|\s)[^.\s]+\.[^.\s]+(?=@)'
string = '''
blah blah blah test.this@gmail.com blah blah
blah blah blah test.this @gmail.com blah blah
blah blah blah test.this.this@gmail.com blah blah
'''
matches = re.findall(expression, string)
print(matches)
['test.this']
If you wish to simplify/modify/explore the expression, it's been explained on the top right panel of regex101.com. If you'd like, you can also watch in this link, how it would match against some sample inputs.
In javascript you have to use \\.
to match a dot.
Example
"blah.tests.zibri.org".match('test\\..*')
null
and
"blah.test.zibri.org".match('test\\..*')
["test.zibri.org", index: 5, input: "blah.test.zibri.org", groups: undefined]
\w
only matches a single character - you probably want\w+