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Key Concept
Exponential Growth and Decay
Basic Answer
Step 1: Understanding the Growth Rate The bacteria population increases by 20% every 10 minutes. This means if the initial population is P, after 10 minutes it becomes P+0.2P=1.2P.
Step 2: Setting Up the Equation for Doubling To find the time when the population doubles, we need to find t such that the population becomes 2P. We use the exponential growth formula: P(t)=P0×(1.2)10t.
Step 3: Solving for t We set P(t)=2P and solve for t: 2P=P×(1.2)10t 2=(1.2)10t
Step 4: Taking the Logarithm To solve for t, take the natural logarithm on both sides: ln(2)=10tln(1.2) t=10×ln(1.2)ln(2)
Step 5: Calculating the Value Using approximate values ln(2)≈0.693 and ln(1.2)≈0.182: t≈10×0.1820.693≈38.1
The time required for the bacteria population to double is approximately 38.1 minutes. The closest option is (b) 40 minutes.
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Super Answer
Step 1: Identify Growth Rate
The bacteria population increases at 20% every 10 minutes. This means if the initial population is P, after 10 minutes it becomes P * (1 + 0.20) = P * 1.2.
Step 2: Establish Doubling Condition
We need to find when the population becomes 2P (double the initial population).
Step 3: Calculate Time for Doubling
Let the number of 10-minute intervals required to double be n. The formula becomes:
P * (1.2)^n = 2P.
Step 4: Simplify the Equation
Cancelling P gives us:
(1.2)^n = 2.
Step 5: Apply Logarithms
Taking the logarithm of both sides:
n * log(1.2) = log(2).
Step 6: Solve for n
Thus,
n = log(2) / log(1.2).
Step 7: Calculate n Using Approximate Log Values
Using approximate values:
log(2) ≈ 0.301 and log(1.2) ≈ 0.0792,
n ≈ 0.301 / 0.0792 ≈ 3.8 (rounded to one decimal).
Step 8: Convert Intervals to Minutes
Since each interval is 10 minutes, total time = 3.8 * 10 = 38 minutes.
Step 9: Round to Nearest Answer Option
The closest answer choice to 38 minutes is 40 minutes.
40 minutes
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