Question: A body was thrown vertically downwards. The velocity upon falling was n timesgreater than the initial velocity.From what height was the body thrown if the time of fall was t?h=(n+1)gt22(n-1)h=(n-1)gt22(n-1)h=(n+1)gt2n-1

A body was thrown vertically downwards. The velocity upon falling was $n$times

greater than the initial velocity.

From what height was the body thrown if the time of fall was t$?$

$h=(n+1)g\frac{t^2}{2}(n-1)$

$h=(n-1)g\frac{t^2}{2}(n-1)$

$h=(n+1)g\frac{t^2}{n-1}$