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Question

If air resistance is negligible, the power required by a car to drive at constant speed up a hill inclined at 30° to the
horizontal is P. What power is required by the car to drive at the same constant speed up a hill inclined at 60° to
the horizontal?
(A) 2P
(B) Greater than P but less than 2P
(C) P
(D) Less than P but greater than P/2
(E) P/2

If air resistance is negligible, the power required by a car to drive at constant speed up a hill inclined at 30° to the horizontal is P. What power is required by the car to drive at the same constant speed up a hill inclined at 60° to the horizontal? (A) 2P (B) Greater than P but less than 2P (C) P (D) Less than P but greater than P/2 (E) P/2

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Asked in United States
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Answer

(B) Greater than P but less than 2P

Explanation

When air resistance is negligible, the power required by a car to drive at constant speed up a hill is given by the equation:
P=mgvsin(θ)P = mgv\sin(\theta)
where P is the power, m is the mass of the car, g is the acceleration due to gravity, v is the velocity of the car, and θ is the angle of the hill

We are given that the power required to drive up a hill inclined at 3030^{\circ} is P

To find the power required to drive up a hill inclined at 6060^{\circ}, we can use the same equation and substitute θ with 6060^{\circ}:
P=mgvsin(60)P' = mgv\sin(60^{\circ})
Since sin(60)=32\sin(60^{\circ}) = \frac{\sqrt{3}}{2}, we can simplify the equation to:
P=32mgvP' = \frac{\sqrt{3}}{2}mgv
Comparing P' with P, we can see that P' is greater than P but less than 2P

Therefore, the answer is (B) Greater than P but less than 2P
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