Berapakah isi padu bekas air itu Gunakan 22 7 Rumus isi padu silinder sup2 tinggi 40 cm lebar 42 cm
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Berapakah isi padu bekas air itu?
(Gunakan 𝜋 = 22/7 , Rumus isi padu silinder = 𝜋𝑗²𝑡)
tinggi=40 cm
lebar=42 cm
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Solution 1
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Solution By Steps
Step 1: Convert Lebar to Jari-jari
Lebar (diameter) dibagi 2 untuk mendapatkan jari-jari (j): 42 cm / 2 = 21 cm.
Lebar (diameter) dibagi 2 untuk mendapatkan jari-jari (j): 42 cm / 2 = 21 cm.
Step 2: Apply the Volume Formula
Gunakan rumus isi padu silinder: 𝜋𝑗²𝑡. Substitusi nilai jari-jari (j) = 21 cm dan tinggi (t) = 40 cm:
Volume = (22/7) * (21 cm)² * 40 cm.
Gunakan rumus isi padu silinder: 𝜋𝑗²𝑡. Substitusi nilai jari-jari (j) = 21 cm dan tinggi (t) = 40 cm:
Volume = (22/7) * (21 cm)² * 40 cm.
Step 3: Calculate the Volume
Hitung (21 cm)² = 441 cm². Kemudian kalikan dengan 40 cm dan 22/7:
Volume = (22/7) * 441 cm² * 40 cm = 55440 cm³.
Hitung (21 cm)² = 441 cm². Kemudian kalikan dengan 40 cm dan 22/7:
Volume = (22/7) * 441 cm² * 40 cm = 55440 cm³.
Final Answer
Isi padu bekas air itu adalah 55440 cm³.
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