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minimal-elements-of-the-prime-numbers/code/cleanf.cc
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//analyser les premiers membres de familles infinies | |
#include <list> | |
#include <string> | |
#include <vector> | |
#include <iostream> | |
#include <fstream> | |
#include <time.h> | |
#include <sstream> | |
#include <stdlib.h> | |
#define factl 100000 | |
using namespace std; | |
// cleans a set of families of numbers (on the standard input) | |
// and sends the result on the standard output | |
// simplifies the repetitions: d{d} => {d} | |
// explicits the first and last digits | |
// drops the copies | |
using sint=long unsigned int; // std::vector<std::__cxx11::basic_string<char> >::size_type; | |
int main(int argc, char *argv[]) | |
{string p; vector <string> res; sint i,l1=0,l2=0; | |
while(cin>>p) | |
{l1++; | |
for(i=0;i<p.size();i++){if(p[i]=='{')while(i!=1&&p[i-1]==p[i+1]){p.erase(i-1,1);i--;} | |
if(p[i]=='}')while(i!=p.size()-2&&p[i+1]==p[i-1])p.erase(i+1,1); | |
if(p[p.size()-1]=='}')p=p+p[p.size()-2]; | |
if(p[0]=='{')p=p[1]+p; | |
} | |
for(i=0;i<res.size();i++)if(p==res[i])break; | |
if(i==res.size()){l2++;res.push_back(p);} | |
} | |
cerr<<"we went from "<<l1<<" to "<<l2<<" items\n"; | |
for(i=0;i<res.size();i++)cout<<res[i]<<"\n"; | |
} // end main | |