I have the following code:
TEMP1=$(awk '$12 == "beacon_server" {print}' < numbers2.log | awk -v var="$i" '{total += $var} EN D {print total/NR}')
Almost the same for the other TEMP-variables.
Now i want to calculate the following and save it in a new variable RESULT:
RESULT=$(expr 100 - $TEMP1 - $TEMP2 - $TEMP3 - $TEMP4)
The error message is telling me that there is a non-integer argument --> expr: non-integer argument
How can I resolve this error?
Error message means that one of the arguments is not an integer to find which and to fix the problem you have to display variables content as the file numbers2.log is not provided we can't find the values.
echo variable
echo "TEMP1=$TEMP1"
...
Or
declare -p ${!TEMP*}
To compute floating point numbers values
exit | awk "END{ print 100 - $TEMP1 - $TEMP2 - $TEMP3 - $TEMP4 }"
or
bc -l <<<"100 - $TEMP1 - $TEMP2 - $TEMP3 - $TEMP4"
expr (notice the print total/NR in the awk command).
May 23, 2017 at 14:42
exit | is to close input redirection for awk awk '...' < /dev/null works also
May 23, 2017 at 15:01
</dev/null instead? Less overhead than setting up a pipeline.
May 23, 2017 at 15:03
TEMPvariables when you get that error? One or more of them isn't an integer. As an aside, preferRESULT=$(( 100 - $TEMP1 - $TEMP2 - $TEMP3 - $TEMP4))to using the external commandexpr.arithmetic expression: expecting EOF: " 100 - 1 - 2.23333 - 0.333333 - 0"