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utt=uxxu
Boundary condition: u(x,0)=f(x),ut(x,0)=0, f(x) is a Schwartz function.

I tried to make u(x,t)=X(x)T(t), then I get XX=TT+T.
Let XX=λ, then X=λX and T+(1λ)T=0.
Then I stuck on that. What should I do next?

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    Do the Fourier transform, get u^tt=ξ2u^u^, solve the ODE to get u^(ξ,t)=f^(ξ)cos1+ξ2t, then do the inverse Fourier transform. – Yuval Feb 5 at 10:02
  • @Yuval I understood the first equation, but how to use boundary condition to get the second equation? – musk Feb 5 at 12:23
  • For any fixed ξ, the equation (u^)tt=(1+ξ2)u^ is a 2nd order linear ODE that one can solve with the initial condition u^(0)=f^ and (u^)(0)=0. – Yuval Feb 6 at 1:42

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