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A line has a slope of Which ordered pairs could be points on a parallel line? Check all that apply.
(-8, 8) and (2, 2)
(-5, -1) and (0, 2)
(-3, 6) and (6.-9)
(-2, 1) and (3,-2)
(0, 2) and (5,5)

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Answer:

B and D

Step-by-step explanation:

Given a line with slope m = - \frac{3}{5}

Since the lines are parallel we require the points with the same slope

Using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = 8, 8) and (x₂, y₂ ) = (2, 2)

m = \frac{2-8}{2-8} = 1 ← not parallel

Repeat with (x₁, y₁ ) = (5, - 1) and (x₂, y₂ ) = (0, 2)

m = \frac{2+1}{0-5} = - \frac{3}{5} ← Parallel

with (x₁, y₁ ) = (- 3, 6) and (x₂, y₂ ) = (6, - 9)

m = \frac{-9-6}{6+3} = - \frac{5}{3} ← not parallel

with (x₁, y₁ ) = (- 2, 1) and (x₂, y₂ ) = (3, - 2)

m = \frac{-2-1}{3+2} = - \frac{3}{5} ← Parallel

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (5, 5)

m = \frac{5-2}{5-0} = \frac{3}{5} ← not parallel

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