Reaction equation for the combustion reaction:
C₈H₈(l) + 10 O₂(g) → 8 CO₂(g) + 4 H₂O(l)
ΔH°c = -42.62kJ per g Styrene
Since styrene has a molar mass of 104.15g/mol
the molar enthalpy of reaction for this combustion reaction is
ΔH°r = -42.62kJ ∙ 104,15 = -4438.9 kJ/mol
According to Hess' law:
ΔH°r = 8∙ΔH°f[CO₂(g)] + 4∙ΔH°f[H₂O(l)] - ΔH°f[C₈H₈(l)]
(oxygen does not appear because enthalpy of formation of the elements in their standard state equals zero)
=>
ΔH°f[C₈H₈(l)] = 8∙ΔH°f[CO₂(g)] + 4∙ΔH°f[H₂O(l)] - ΔH°r
= 8∙(- 393.5 kJ/mol) + 4∙(-285.8kJ/mol) - (-4438.9kJ/mol)
= 147,7 kJ/mol
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I dont get it!
How did you get that ΔH°r= -4438.9kJ/mol, if the problem says it is 42.62kJ per gram (positive, and not negative) I don't understand where the negative sign comes from.
I keep doing this problem and get -8730
Please help!! :(