How do I convert an epoch timestamp to a human readable format on the cli?

date -d @1190000000 Replace 1190000000 with your epoch

$ echo 1190000000 | perl -pe 's/(\d+)/localtime($1)/e' 
Sun Sep 16 20:33:20 2007

This can come in handy for those applications which use epoch time in the logfiles:

$ tail -f /var/log/nagios/nagios.log | perl -pe 's/(\d+)/localtime($1)/e'
[Thu May 13 10:15:46 2010] EXTERNAL COMMAND: PROCESS_SERVICE_CHECK_RESULT;HOSTA;check_raid;0;check_raid.pl: OK (Unit 0 on Controller 0 is OK)

With bash-4.2 or above:

printf '%(%F %T)T\n' 1234567890

(where %F %T is the strftime()-type format)

That syntax is inspired from ksh93.

In ksh93 however, the argument is taken as a date expression where various and hardly documented formats are supported.

For a Unix epoch time, the syntax in ksh93 is:

printf '%(%F %T)T\n' '#1234567890'

ksh93 however seems to use its own algorithm for the timezone and can get it wrong. For instance, in Britain, it was summer time all year in 1970, but:

$ TZ=Europe/London bash -c 'printf "%(%c)T\n" 0'
Thu 01 Jan 1970 01:00:00 BST
$ TZ=Europe/London ksh93 -c 'printf "%(%c)T\n" "#0"'
Thu Jan  1 00:00:00 1970

The two I frequently use are:

$ perl -leprint\ scalar\ localtime\ 1234567890
Sat Feb 14 00:31:30 2009

and

$ tclsh
% clock format 1234567890
Sa Feb 14 00:31:30 CET 2009

Custom format with GNU date:

date -d @1234567890 +'%Y-%m-%d %H:%M:%S'

Or with GNU awk:

awk 'BEGIN { print strftime("%Y-%m-%d %H:%M:%S", 1234567890); }'

Linked SO question: https://stackoverflow.com/questions/3249827/convert-from-unixtime-at-command-line

With zsh you could use the strftime builtin:

strftime format epochtime

      Output the date denoted by epochtime in the format specified.

e.g.

zmodload zsh/datetime
strftime '%A, %d %b %Y' 1234567890

Friday, 13 Feb 2009

There's also dateconv from dateutils:

dateconv -i '%s' -f '%A, %d %b %Y' 1234567890

Friday, 13 Feb 2009

keep in mind dateutils tools default to UTC (add -z your/timezone if needed).

If your epoch time is in milliseconds instead of seconds, remove the last three digits before passing it to date -d:

$ date -d @1455086371603
Tue Nov  7 02:46:43 PST 48079     #Incorrect

This gives incorrect data. Remove the last three digits.

$ date -d @1455086371
Tue Feb  9 22:39:31 PST 2016      #Correct after removing the last three digits. You may remove and round off the last digit too.

You could also use a little C program for printing the datetime in the format that can be directly parsed by shell

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

int main(int argc, char * argv[]) {

    if (argc==1) { 
        return 1;
    }

    struct tm input_tm;
    char * formatStr  = "YEAR=%Y\nMON=%m\nDAY=%d\nHOUR=%H\nMIN=%M\nSEC=%S";
    size_t formatSize = strlen(formatStr) + 2;
    char * output     = (char *)malloc(sizeof(char)*formatSize);

    strptime(argv[1],"%s",&input_tm);
    strftime(output, formatSize, formatStr, &input_tm);

    printf("%s\n",output);
    free(output);
    return 0;
}

usage:

#compile
clang -o epoch2datetime main.c

#invoke
eval `./epoch2datetime 1450196411`
echo $YEAR $MON $DAY $HOUR $MIN $SEC
#output
#2015 12 16 00 20 11

Wouldn't be a real solution without a little node.js:

epoch2date(){
    node -p "new Date($1)"
}

add that to ~/.bash_aliases and make sure its sourced in ~/.bashrc with . ~/.bash_aliases

if [ -f ~/.bash_aliases ]; then
    . ~/.bash_aliases
fi

To get node on your system goto http://nvm.sh and run the curl command. It'll install node version manager (nvm) which allows you to switch versions of node.

Just type nvm ls-remote and pick a version to nvm install <version>.

PowerShell – Convert Unix or Epoch time to readable format

http://winplat.net/2015/12/14/powershell-convert-unix-or-epoch-time-to-readable-format/