Training ticket
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Session
ID: trainingYSRZQ4-YF4
Time limit: 120 min.
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Status: closed
Created on:
2018-01-12 06:35 UTC
Started on:
2018-01-12 06:35 UTC
Finished on:
2018-01-12 06:35 UTC
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Tasks in test | Correctness | Performance | Task score | |
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1
TapeEquilibrium
Submitted in: PHP
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100%
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A non-empty zero-indexed array A consisting of N integers is given. Array A represents numbers on a tape.
Any integer P, such that 0 < P < N, splits this tape into two non-empty parts: A[0], A[1], ..., A[P − 1] and A[P], A[P + 1], ..., A[N − 1].
The difference between the two parts is the value of: |(A[0] + A[1] + ... + A[P − 1]) − (A[P] + A[P + 1] + ... + A[N − 1])|
In other words, it is the absolute difference between the sum of the first part and the sum of the second part.
For example, consider array A such that:
A[0] = 3 A[1] = 1 A[2] = 2 A[3] = 4 A[4] = 3We can split this tape in four places:
- P = 1, difference = |3 − 10| = 7
- P = 2, difference = |4 − 9| = 5
- P = 3, difference = |6 − 7| = 1
- P = 4, difference = |10 − 3| = 7
Write a function:
function solution($A);
that, given a non-empty zero-indexed array A of N integers, returns the minimal difference that can be achieved.
For example, given:
A[0] = 3 A[1] = 1 A[2] = 2 A[3] = 4 A[4] = 3the function should return 1, as explained above.
Assume that:
- N is an integer within the range [2..100,000];
- each element of array A is an integer within the range [−1,000..1,000].
Complexity:
- expected worst-case time complexity is O(N);
- expected worst-case space complexity is O(N), beyond input storage (not counting the storage required for input arguments).
The solution obtained perfect score.
https://codility.com/demo/take-sample-test/tape_equilibrium/