I read that the weight ratio of an aircraft after and before landing, was larger than the ratio after and before takeoff. The weight is lost only due to fuel burn, so why does an aircraft appear to consume more fuel during takeoff than during landing? How does the 'ground effect' play a role here?

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Is this question serious? – Peter Jun 21 at 11:38
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@Peter Yes, quite serious. Why do you ask? – ShruKam Jun 21 at 11:45
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Do you not find walking up a hill requires more effort than walking down a hill? @SkruKam – andy-m Jun 21 at 12:27
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@andy-m This is an open and welcoming forum, please don't ridicule people's questions – Steve Kuo Jun 21 at 16:35
up vote 13 down vote accepted

Ground effect plays very little here.

When taking off and climbing you need to add kinetic energy and potential energy to the plane in terms of speed and height. Getting that energy requires burning fuel.

When landing you want to get rid of that energy. Easiest way is to turn down the engine (or off when something breaks) and let drag slow you down and trade height for speed.

When taking off the plane will also be heavier because it will have more fuel on board. So it takes more energy to speed it up and get it up high.

It's very similar to climbing a hill and descending a hill, going up takes energy and going down means you can coast.

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