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Batch File - Replacing double quotes in a text file
Posted on 2004-06-30
How can I replace double quotes in a text file using a batch file?
I've seen a couple of answers pointing to http://www.batchfiles.co.nr but the example there doesn't appear to work if the string you are looking to replace is ".
I thought I could do it by reading the contents of the file into a variable and then using SET, but I can't find out how to read the file into a variable.
Or can I use a FOR loop which looks at each line in the file as a whole, rather than splitting the line using delimiters?
Thanks,
Angie
I've seen a couple of answers pointing to http://www.batchfiles.co.nr but the example there doesn't appear to work if the string you are looking to replace is ".
I thought I could do it by reading the contents of the file into a variable and then using SET, but I can't find out how to read the file into a variable.
Or can I use a FOR loop which looks at each line in the file as a whole, rather than splitting the line using delimiters?
Thanks,
Angie
2 Comments
This batch file changes " to ' in the file passed on the command line. The results are written to output.txt.
@echo off
setlocal
if "%1"=="" echo Please enter file name&goto :EOF
if exist output.txt del output.txt > NUL
for /f "delims=" %%a in ('type %1') do call :PROCESS "%%a"
echo Output.txt has results
goto :EOF
:PROCESS
set line=%~1
REM Replace double quote with single quote
set line=%line:"='%
echo %line%>>output.txt
Good Luck,
Steve
@echo off
setlocal
if "%1"=="" echo Please enter file name&goto :EOF
if exist output.txt del output.txt > NUL
for /f "delims=" %%a in ('type %1') do call :PROCESS "%%a"
echo Output.txt has results
goto :EOF
:PROCESS
set line=%~1
REM Replace double quote with single quote
set line=%line:"='%
echo %line%>>output.txt
Good Luck,
Steve
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