Every np problem is an aggregation of p problems. Therefore p = np. Any notion of an np problem is due to the misidentification or overlook of any of the p problems involved within it. Every np problem can be reimagined or restructured as a p problem. The very nature of this question (p=np?) as unanswerable is the only thing which has kept it from being answered. This is the same as saying that because we have chosen to see p and np as different, they both exist. However we see in reality neither really does since non-polynomial is really expressed directly through polynomial. Therefore every problem is polynomial, but this loses all meaning, what is a polynomial problem? There are therefore just problems, in the sense they can no longer be classified as either p or np. The fact that they are called hard speaks to the relativity of the matter. Hard for the mathematicians which decided it was hard. A fourth grader cannot solve an equation: X + 7 = 9. The fourth grader calls this hard. However the fourth grader faces a world where many many people have solved that problem. And therefore one day they see it is not hard (if they proceed with their math learning). Is it any harder than any problem? Any easier? P = np is a problem itself, considered so by all. This is all that makes it a problem. We have chosen to see p and we have chosen to see np.