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[–]EducatedRetard -13 ポイント-12 ポイント

Edit: Since Reddit apparently is a fan of misinformation. Fuck you. Now none of you get to know the correct answer.

[–]PyroNavi 8 ポイント9 ポイント

Edit: Since Reddit apparently is a fan of misinformation. Fuck you. Now none of you get to know the correct answer.

Punishing many for crimes of the few, I see.

[–]VeXCe 2 ポイント3 ポイント

The reflective layer is being removed, the actual data is in the plastic layer and is probably still there.

Edit: OR NOT! See this guy for something different: http://www.reddit.com/r/Damnthatsinteresting/comments/25g55p/electricity_dumped_on_a_cd/chh2eop

[–]sphks 1 ポイント2 ポイント

Isn't it different if it's a CD and a CD-R ? A CD is pressed to reproduce pits, so the data are on the plastic layer. A CD-R is burned, so the data are on the reflective layer.

[–]jeffredd 1 ポイント2 ポイント

Yes and no. On a CD Rom the mirror of the data is in the polycarbonate as a bi-product of the manufacturing process. But the data is technically encoded in the aluminum since that is what causes the different values to be read.

If you had a perfectly flat reflective layer but bumps and pits in the polycarbonate, you wouldn't be able to read any data. The reflection would be uniform and wouldn't provide the variance that is what translates to the data.

[–]VeXCe 1 ポイント2 ポイント

CD-R's use dyes, but CD-RW does use a metal alloy for its storage.

[–]jeffredd 0 ポイント1 ポイント

Cool. I didn't realize that.

[–]geophsmith 0 ポイント1 ポイント

Well I don't think I've ever seen a username more accurate than that one.

[–]EducatedRetard 0 ポイント1 ポイント

[–]nebulouscloud 0 ポイント1 ポイント

You're living up to your name with your edit.